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solute s has a distribution constant of 4.44.4 between water (phase 1) and hexane (phase 2). calculate the concentration of solute s in hexane

Sagot :

The concentration of solute s in hexane  is 11.62.

Given

Partifion coefficient [tex]$=4 \cdot 4$[/tex]

[tex]$\begin{aligned}\text { Partition coebbicient } & =\frac{[\text { Shexane }]}{[\text { Swak] }]} \\4 . 4 & =\frac{[\text { Sherate }]}{0.024} \\{[\text { Snewane }] } & =4.4 \times 0.024 \mathrm{~m} \\& =0.1056 \mathrm{~m} \\& =0.10 \mathrm{~m}\end{aligned}$[/tex]

[tex]\begin{aligned}& \text { Partition coetficient }=\frac{\frac{\text { moles }}{\text { volune }} \text { of } \sin \text { Lexane }}{\frac{\text { moles }}{\text { vilum }} \text { ob } s \text { in }} \\& 4.4=\frac{\frac{\text { mol sherake }}{24.0 \mathrm{~mL}}}{\frac{\text { molwater. }}{65.0 \mathrm{~mL}}} \\& \frac{\text { mol S hexare }}{\text { mol } S_{\text {watex }}}=\frac{4.4 \times 84.0 \mathrm{~mL}}{65.0 \mathrm{~mL}} \\& =1.624 \\& =11.62 \\&\end{aligned}[/tex]

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