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Sagot :
The area of the Rhombus ABCD is 1.2 square meter.
What is Rhombus?
A quadrilateral with four equal-length sides is known as a Rhombus in plane Euclidean geometry. Another name for this shape is an equilateral quadrilateral because all of its sides are equal in length.
Let ABCD be the given Rhombus of Perimeter = 52 cm.
Since all the sides are equal to each other.
Therefore, each side of Rhombus measures = 13 cm
So,
AD = CD = 13 cm and AC = 24 cm.
Area of the triangle ACD = √[ s (s - a) (s - c) (s - d) ] ….. Heron’s Formula.
where s = semi-perimeter,
a, c, and d are side measures.
s = (1/2) [ 13 + 13 + 24 ] = 25
Area (A) = √[ 25 (25 – 13) (25 – 13) (25 - 24) ] = 60
Hence Area of the entire Rhombus = 2 * 60 = 120 cm²
Convert 120 cm^2 into meter square
⇒ 120 cm^2 = 1.2 m^2
Hence, the area of the Rhombus ABCD is 1.2 square meter.
To know more about Rhombus, click on the link
https://brainly.com/question/20627264
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