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the combustion of ammonia in the prescne of excess oxygen yield no2 and h2o. how many grams of no2 are produced when 43.9mg of ammonia burn

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rafikiedu08

The combustion of ammonia in the prescne of excess oxygen yield no2 and h2o. 0.119  grams of no2 are produced when 43.9mg of ammonia burn.

Molar mass of NH3 = 1*MM(N) + 3*MM(H)

= 1*14.01 + 3*1.008

= 17.034 g/mol

mass of NH3 = 0.0439 g

mol of NH3 = (mass)/(molar mass)

= 0.0439/17.034

= 2.577*10^-3 mol

From balanced chemical reaction, we see that

when 4 mol of NH3 reacts, 4 mol of NO2 is formed

mol of NO2 formed = moles of NH3

= 2.577*10^-3 mol

Molar mass of NO2 = 1*MM(N) + 2*MM(O)

= 1*14.01 + 2*16.0

= 46.01 g/mol

mass of NO2 = number of mol * molar mass

= 2.577*10^-3*46.01

= 0.119 g

To learn more about Molar mass visit:https://brainly.com/question/22997914

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