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a rigid tank contains 1 kg propane at 500k, 1500 kpa. it is now cooled down to 300 k. find the ehat transfer and the change in entropy

Sagot :

the heat transfer and the change in entropy is −0.8868  kJ/K.

how to solve ?

Ideal gas, constant volume so there is no work.

m (u₂ -u₁) = ₁Q₂ ₋ ₁w₂ = ₁Q₂

u₂ ₋ u₁ = Cv (T₂ ₋ T₁) = 1.736(300 - 500) = 347.2kJ/Kg

₁Q₂ = m (u₂ - u₁ ) = 1(-347.2) = -347.2kj

the change in s for an ideal gas v₂ = v₁ gives

m(s₂ - s₁ ) = m [Cv₀ In T₁/T₂ + R In T₂/T₁

= 1kg ˣ 1.736kj / kg - K In 300/500 = -0.8868kJ/K

What is a simple definition of entropy?

the amount of thermal energy per unit of temperature in a system that cannot be used for productive work. Entropy is a measure of a system's molecular disorder or unpredictability since work is produced by organized molecular motion.

What does a negative change in entropy mean?

Entropy is the amount of disorder in a system. Disorder is much more probable than order in a random system. So if entropy is the amount of disorder, negative entropy means something has less disorder, or more order.

learn more about entropy visit :

https://brainly.com/question/13146879

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