Westonci.ca offers quick and accurate answers to your questions. Join our community and get the insights you need today. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
The probability of obtaining between 9 and 14 heads is .0.0408
Probability:
in statistics, probability refers the possibility of the outcome of any random event.
Given,
A coin is weighted so that the probability of obtaining a head in a single toss is 0.25.
Here we need to find the probability of obtaining between 9 and 14 heads if the coin is tossed 45 times.
While we looking into the given question,
Probability of obtaining a head in a single toss = 0.25
Number of toss = 45
Here we need to find the probability of getting head between 9 and 14, is calculated as,
=> mean = 45 x 0.25 = 11.25
=> standard deviation = √11.25 x(1 - 0.25) = 2.9
Here the probability is written as,
=> P(9 < x < 14) = P(8.5 < x < 14.5)
Then the z score, is
=> z = (8.5 - 11.25)/2.9 = -0.9483
=> z = (14.5 - 11.25)/2.9 = 1.1207
So, the given probability is rewritten as,
=> P(9 < x < 14) = P(z < 1.1207) - P(z < 0.9483)
When we apply the value of z score on it then we get,
= > P(z < -0.9483) = 0.17149
=> P(z > 1.1207) = 0.13121
=> P(9 < x < 14) = 0.13121 - 0.17149
=> 0.0403
To know more about Probability here.
https://brainly.com/question/11234923
#SPJ4
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.
