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. suppose 32.8 g of hydrochloric acid is mixed with 9.7 g of sodium hydroxide. calculate the maximum mass of water that could be produced by the chemical reaction. round your answer to 2

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The maximum mass of NaCl that could be produced by chemical reaction is 14.03grams

What is Stoichiometry?

Stoichiometry is a branch of chemistry that includes determining desired quantitative data by exploiting relationships between reactants and/or products in a chemical process.

Stoichiometric challenges are grouped into various types:  Mass to mass conversion. Mass to moles conversion. Mole to mass steps conversion.

What is limiting agent?

The limiting reagent is the reactant that is totally consumed in a reaction, determining when the reaction comes to a halt. The exact amount of reactant required to react with another element can be estimated using reaction stoichiometry.

Given,

Mass of hydrochloric acid = 32.8 grams

Molar mass of hydrochloric acid (HCl)= 36.46 g/mol

Mass of sodium hydroxide = 9.7 grams

Molar mass of sodium hydroxide = 40.0 g/mol

According to the question, equation would be :

[tex]HCl + NaOH[/tex]  → [tex]NaCl + H_2O[/tex]

moles of HCl = Given mass of HCl / Molar mass of HCl

moles of HCl = 32.8 / 36.46 = 0.899 ≅ 0.90moles

moles of NaOH = Given mass of NaOH / Molar mass of NaOH

moles of NaOH  = 9.7 / 40.0 = 0.242 ≅ 0.24moles

Here, NaOH is a limiting factor, so it will be consumed completely. But moles of HCl are in excess.

So, only 0.24moles of HCl will be consume and remaining will be 0.90moles - 0.24moles = 0.66moles.

When 1 mol HCl react with 1 mol NaOH it produce 1 mol NaCl and 1 mol [tex]H_2O[/tex]

For 0.24moles of NaOH, we will have 0.24moles of NaCl

Maximum mass of NaCl = no. of moles of NaCl * molar mass of NaCl

mass of NaCl = 0.24 * 58.44 = 14.0256 ≅14.03grams

mass of NaCl ≅14.03grams

The maximum mass of NaCl that could be produced by chemical reaction is 14.03grams

To know more about limiting agent, check out:

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