Answered

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(a) what is the period of small-angle oscillations of a simple pendulum with a mass of 0.6 kg at the end of a string of length 5 m?

Sagot :

Answer:

T = 2 π (L / g)^1/2

T = 6.28 (5 m / 9.80 m/s^2)^1/2

T = 4.49 sec     (the period is not dependent on mass)

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