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(a) A cyclit rode hi bike for 169 min at an average velocity of 3. 53 m/ on a bearing of 450. Find hi total diplacement in km a a vector in the form i and j (3 mark)

Sagot :

The total displacement in km and vector form in the form of i and j is 35.8 a[x] km + 0 a[y] km.

According to the question,

We have the following information:

A cyclist rode his bike for 169 min at an average velocity of 3. 53 m/s on a bearing of 450.

Now, we know that the following formula is used to find the velocity:

Velocity = displacement/time

(We will convert time from minutes into seconds.)

Displacement = 3.53*(169*60)

Displacement = 35794.2 m

Now, the displacement in km will be 35.8 km approximately.

Now, let's take that the bike is moving along the positive x-axis. So, it would be written in the following expression:

Displacement = 35.8 a[x] km + 0 a[y] km

Hence, the total displacement in km and vector form in the form of i and j is 35.8 a[x] km + 0 a[y] km.

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