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Sagot :
An equation of line having slope 1/6 and passes through the point (0,-3) is y = 1/6x - 3
We know that the slope-point form of line is:
(y - y1) = m(x - x1)
Here, we need to find an equation of line having slope 1/6 and passes pae through the point (0,-3)
let (x1, y1) = (0, -3)
and m = 1/6
substitute values in above formula,
(y - (-3)) = 1/6 (x - 0)
y + 3 = 1/6 (x)
y = 1/6x - 3
which is slope-intercept form of line (y = mx + b)
Therefore, equation of line is y = 1/6x - 3
Learn more about equation of line here:
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