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Find the equation of a line perpendicular to y=4/3x8 that pae through the point (-8,-4)

Sagot :

The equation of a line perpendicular to y=4/24x that pass through the point (-8, -4) is -6x-4y=16 where x-intercept is -6 and y-intercept is -4.

What is an equation or line?

A linear equation is an algebraic equation of the form y=mx+b, where m is the slope and b is the y-intercept, and only a constant and a first-order (linear) term are included. The variables in the preceding equation are y and x, and it is occasionally referred to as a "linear equation of two variables.

What is equation of a straight line?

The formula for a straight line is y=mx+c where c is the height at which the line intersects the y-axis, often known as the y-intercept, and m is the gradient.

Given line ;

y=1x/6

now comparing it with y=mx+c to find the value of m and we found;

m1=1/6

now if two lines are perpendicular then,

m1.m2=-1

m2=-6

now finding the equation of line passing through the point (-8, -4)

x1=-8

y1=-4

(y−y1)=m(x−x1)

Y+4=(-6)(x+4)

Y+4=(-6x/4)

Y=(-6x/4)-4

Y=(-6x-16)/4

4y=-6x-16

rearrange;

-6x-4y=16

this is our required value.

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