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Find the equation of the line in tandard form that pae through the point (1, -3) and (-2, -1)

Sagot :

The equation of line in standard form that pass through the point (1, -3) and (-2, -1) is (-2x/3)-y=7/3 where -2/3 is x-intercept and -1 is the y-intercept.

What does the straight line equation mean?

A straight line's equation is given by y=mx+c, where c is the height at which the line intersects the y-axis (often referred to as the y-intercept) and m is the gradient.

Why is there an equation of a line?

The set of points that make up a line in a coordinate system are represented algebraically by a line's equation. An equation of a line is an algebraic expression that represents the many points that together make up a line in the coordinate axis as a set of variables, x, and y.

we are given with;

x1=1, y1=-3

x2=-2, y2=-1

equation of line in standard form:

Ax+By=C

so using formula:

(y−y1)=(y2−y1)(x−x1)/(x2−x1)

(y−(-3))=((-1)−(-3))(x-1)/(-2−1)

(y+3)=(2)(x−1)/(-3)

(y+3)=(2x−2)/(-3)

y+3=(-2x/3)+(2/3)

y=(-2x/3)+(2/3)-3

y=(-2x+2-9)/3

y=(-2x-7)/3

(2x/3)+y=-7/3

rearranging;

(-2x/3)-y=7/3

This is our required answer.

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