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A baseball is thrown in a parabolic arc. It's position above the ground at a given point in
time can be represented by the quadratic function p (t) = gt² + vot + po, where
t> 0. g is -32 ft/sec/sec, vo is initial velocity, and po is its initial position above the
ground. If the ball was thrown straight up at 16 ft/sec when it was 5 ft above the
ground, how high did it go?

Sagot :

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