Let a,b,c be positive real numbers. Prove the inequality
[tex]\displaystyle\\\bf\frac{(a+b)^2}{c} +\frac{c^2}{a} \geq 4b[/tex]

Question

04-12-2022
Mathematics

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Let a,b,c be positive real numbers. Prove the inequality
[tex]\displaystyle\\\bf\frac{(a+b)^2}{c} +\frac{c^2}{a} \geq 4b[/tex]

$Let Abc Be Positive Real Numbers Prove The Inequality Texdisplaystylebffracab2c Fracc2a Geq 4btex class=$

Sagot :

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Let a,b,c be positive real numbers. Prove the inequality [tex]\displaystyle\\\bf\frac{(a+b)^2}{c} +\frac{c^2}{a} \geq 4b[/tex]

Sagot :

Other Questions

Let a,b,c be positive real numbers. Prove the inequality
[tex]\displaystyle\\\bf\frac{(a+b)^2}{c} +\frac{c^2}{a} \geq 4b[/tex]