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Barium metal crystallizes in a body-centered cubic lattice (the Ba atoms are at the lattice points only). The unit cell edge length is 502 pm, and the density of the metal is 3. 50 g/cm3. Using this information, calculate Avogadro's number. [Hint: First calculate the volume (in cm3) occupied by 1 mole of Ba atoms in the unit cells. Next calculate the volume (in cm3) occupied by one Ba atom in the unit cell. Assume that 68% of the unit cell is occupied by Ba atoms. ]

Sagot :

The Avogadro' s number is 6.022×10²³

What is body centered cubic lattice?

The Bravis lattice of the same name serves as the basis for the BCC crystal structure, which has one atom per lattice point at each of the cube's four corners and in its centre. BCC's high proportion of nearest and next-nearest neighbours contributes to its tight proximity and excellent stability.

atomic mass of Ba = 137.327u

No. of atoms of Ba in a BCC unit cell = 2

Edge length of unit cell= 502pm =502ₓ10⁻¹⁰ cm

density =3.50g/cm³

ρ=ZM/N₀ₓV

3.50=2ₓ137.327/N₀ₓ(502ₓ10⁻¹⁰)³

=78.47257/1.265ₓ10⁻²²

N₀=6.02ₓ10²³

For more information about body centred lattice please visit:

https://brainly.in/question/1033664

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