Answered

Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

how to claculate (b) what fraction of the chemical energy transformed appears as internal energy in the batteries?

Sagot :

tutorconsortium272

a.) The resistance of the bulb is calculated l to be 4.58 Ohm and b.) The fraction of the chemical energy transformed which appears as internal energy in batteries is 8.4%.

What is electromotive force?

Energy transfer to an electric circuit per unit of electric charge measured in volts is called electromotive force .

Given, Voltage= 1.5 Volts

Internal resistance A  is 0.240 Ohms

Internal resistance B is 0.180 Ohms

and current = 600 mA = 0.6 Amps

a. To find resistance of the bulb:

The total electromotive force (E) of the electric circuit:

E = 2*1.5

= 3.0 Volts

Total internal resistance = 0.240 + 0.180 = 0.42 ohms

Electromotive force (E) is given by the formula:

E= V+ I r

E is electromotive force

V is  voltage and I is the current.

r is internal resistance.

Ohm's law is given by:

V= I R

Given, Resistance, R = 4.58 Ohms

E = IR + I r

R= E/I - r

= (3/0.6) - 0.42

= 4.58 ohms

b. To determine what fraction of chemical energy transformed appears as internal energy in batteries:

the electromotive force (E) in the batteries. E b = I R

= 0.6 * 0.42

= 0.252 Volt

Percent= (Eb / E) * 10

=0.252/3

percent = 8.4 %

To know more about electromotive force, refer

https://brainly.com/question/24168205

#SPJ4

Note: The question given on the portal is incomplete. Here is the complete question.

Question : Two 1.50-V batteries—with their positive terminals in the same direction—are inserted in series into the barrel of a flashlight. One battery has an internal resistance of 0.240 Ω, the other an internal resistance of 0.180 Ω. When the switch is closed, a current of 600 mA occurs in the lamp. (a) What is the bulb's resistance? Ω (b) What fraction of the chemical energy transformed appears as internal energy in the batteries? %

We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.