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how to claculate (b) what fraction of the chemical energy transformed appears as internal energy in the batteries?

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a.) The resistance of the bulb is calculated l to be 4.58 Ohm and b.) The fraction of the chemical energy transformed which appears as internal energy in batteries is 8.4%.

What is electromotive force?

Energy transfer to an electric circuit per unit of electric charge measured in volts is called electromotive force .

Given, Voltage= 1.5 Volts

Internal resistance A  is 0.240 Ohms

Internal resistance B is 0.180 Ohms

and current = 600 mA = 0.6 Amps

a. To find resistance of the bulb:

The total electromotive force (E) of the electric circuit:

E = 2*1.5

= 3.0 Volts

Total internal resistance = 0.240 + 0.180 = 0.42 ohms

Electromotive force (E) is given by the formula:

E= V+ I r

E is electromotive force

V is  voltage and I is the current.

r is internal resistance.

Ohm's law is given by:

V= I R

Given, Resistance, R = 4.58 Ohms

E = IR + I r

R= E/I - r

= (3/0.6) - 0.42

= 4.58 ohms

b. To determine what fraction of chemical energy transformed appears as internal energy in batteries:

the electromotive force (E) in the batteries. E b = I R

= 0.6 * 0.42

= 0.252 Volt

Percent= (Eb / E) * 10

=0.252/3

percent = 8.4 %

To know more about electromotive force, refer

https://brainly.com/question/24168205

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Note: The question given on the portal is incomplete. Here is the complete question.

Question : Two 1.50-V batteries—with their positive terminals in the same direction—are inserted in series into the barrel of a flashlight. One battery has an internal resistance of 0.240 Ω, the other an internal resistance of 0.180 Ω. When the switch is closed, a current of 600 mA occurs in the lamp. (a) What is the bulb's resistance? Ω (b) What fraction of the chemical energy transformed appears as internal energy in the batteries? %

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