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choose each digit of a 5 digit number at random from digits 1, . . . , 9. compute the probability that no digit appears more than twice.

Sagot :

The probability that no digit appears more than twice is 0.648.

What is probability?

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

Here,

We will choose each digit of 5-digit numbers at random from digits 0,1,2,..,9.

We have to compute the probability that no digit appears more than twice.

So, we have to form a five-digit number say "abcde".

Now, for 'a' we have 10 choices.

For 'b' we have again 10 choices because a digit can appear at most two.

For 'c' we have 9 choices because the digit in 'a' can not be chosen as a digit can appear at most two.

For 'd' we have again 9 choices by a similar argument.

Finally, for 'e' we have 8 choices because the digit chosen previously can not be repeated more than twice.

The total number of such 5-digit numbers is = 10*10*9*9*8 = 64800.

Now, a total number of 5-digit numbers = 10*10*10*10*10 = 100000.

Hence, the probability that no digit appears more than twice is given by,

= 64800/ 100000

= 0.648

Hence, the probability that no digit appears more than twice is 0.648.

To learn more about the probability from the given link

https://brainly.com/question/24756209

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