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Sagot :
The value of a , b and c are 7, 11 and 1 respectively.
173a is divisible by 9.
Rule of divisible by 9 is:
The number itself is divisible by 9 if its digit sum is also divisible by 9.
digits sum = 1+7+3+a = 11+a.
11+a is divisible by 9. a can be 7 so that 11+7 = 18 is divisible by 9.
minimum positive value of a = 7.
173b is divisible by 11
Rule of divisible by 11 is:
A number is completely divisible by 11 if the difference between the sum of its alternative digits is divisible by 11.
sum of its alterative digits:
1+3 =4
7+b =7+b
difference of alternative digits sum = 7+b-4 = b+3 is divisible by 11 b = 8
so that 8+3 = 11 is divisible by 11.
minimum positive value of b = 11.
173c is divisible by 6.
Rule of divisible by 11 is:
Any number that can be divided by both 2 and 3 is also divisible by 6.
sum of digits of number = 1+7+3+c = 11 + c if divisible by 2 then it should be even if we put c = 1 , 11+1 = 12 which is divisible by both 2 and 3.
minimum positive value of c = 1.
So the value of a ,b and c are 7, 11 and 1 respectively.
To know more about divisibility here
https://brainly.com/question/10703980
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