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Sagot :
The height of the image is 0.00283 m and it is inverted.
Given,
The object distance, u = 6 meters
The distance of lens from retina, v = 1.7 cm
The object height, hu = 1 m
We have to find the size of letters that appears in the retina, hv;
Magnification;
Magnification is the process of enlarging something's apparent size rather than its actual size. This enlargement is measured in terms of a calculated quantity known as "magnification." The term "magnification" or "de-magnification" is frequently used to describe a reduction in size when this number is less than one.
Here,
Magnification, M = -v/u = hv/hu
- 0.017/6 = hv/1
hv = -0.017/6
hv = -0.002833m
The image is of 0.00283 m height and it is inverted because of negative sign.
Learn more about magnification here;
https://brainly.com/question/13258928
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