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At a distance of 6 meters, a person with average vision is able to clearly read letters 1.0 cm high.Approximately how large do the letters appear on the retina? (Assume that the retina is 1.7 cm from the lens.)

Sagot :

The height of the image is 0.00283 m and it is inverted.

Given,

The object distance, u = 6 meters

The distance of lens from retina, v = 1.7 cm

The object height, hu = 1 m

We have to find the size of letters that appears in the retina, hv;

Magnification;

Magnification is the process of enlarging something's apparent size rather than its actual size. This enlargement is measured in terms of a calculated quantity known as "magnification." The term "magnification" or "de-magnification" is frequently used to describe a reduction in size when this number is less than one.

Here,

Magnification, M = -v/u = hv/hu

- 0.017/6 = hv/1

hv = -0.017/6

hv = -0.002833m

The image is of 0.00283 m height and it is inverted because of negative sign.

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