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If the difference follows the Normal​ model, what's the probability that the small bowl contains more cereal than the large​ one?

Sagot :

The probability that the small bowl contains more cereal than the large​ one is 0.0228.

Given :

The amount of cereal that can be poured into a small bowl varies with a mean of 1.5 ounces and a standard deviation of 0.3 ounces. A large bowl holds a mean of 2.5 ounces with a standard deviation of 0.4 ounces. You open a new box of cereal and pour one large and one small bowl.

we know that,

z = x - μ / σ

here

x = 0

μ = 1

σ = 0.5

= 0 - 1 / 0.5

= -1/0.5

= -1 / 05 / 10

= -1 * 10 / 5

=  -10 / 5

= -2

if z = -2 then p value = 0.0228

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Full question :

The amount of cereal that can be poured into a small bowl varies with a mean of 1.5 ounces and a standard deviation of 0.3 ounces. A large bowl holds a mean of 2.5 ounces with a standard deviation of 0.4 ounces. You open a new box of cereal and pour one large and one small bowl.

If the difference follows the Normal​ model, what's the probability that the small bowl contains more cereal than the large​ one?