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Raise your hand and hold it flat. Think of the space between your index finger and your middle finger as one slit, and think of the space between middle finger and ring finger as a second slit.(a) Consider the interference resulting from sending coherent visible light perpendicularly through this pair of openings. Calculate the angle between adjacent zones of constructive interference, assuming the width of your middle finger to be 2.7 cm and the wavelength of the light to be 700 nm.(b) To make the angles in the interference pattern easy to measure with a plastic protractor (e.g., for which the angle between the central maximum and the adjacent ones is 15�), you should use an electromagnetic wave with what frequency?HzHow is this wave classified on the electromagnetic spectrum?

Sagot :

KunalYadav273

Angle and frequency between neighboring zones for constructive interference are both 1.846 * 103⁻³ degrees and 6.44 * 10¹⁰ Hz, respectively.

What exactly is regularity and why is it significant?

The quantity of oscillations that pass a given point in one unit of time, as well as the number of passes or oscillations that an object in periodic motion experiences in one unit of time Multiple electrical frequencies cannot coexist without causing device damage, hence keeping a constant electrical rate is crucial. When it comes to supplying power on a national basis, this has important ramifications.

Briefing:

a). For Constructive interference;

[tex]$\begin{aligned}& d \sin \theta=m \lambda \\& \theta=\sin ^{-1}\left(\frac{m \lambda}{d}\right)=\sin ^{-1}\left(\frac{1 \times 580 \times 10^{-9}}{0.018}\right) \\& \theta=1.846 \times 10^{-3} \text { degreees }\end{aligned}$[/tex]

Angle between nearby constructive interference zones;

[tex]$\Delta \theta=1.846 \times 10^{-3}-0=1.846 \times 10^{-3} \text { degrees }$[/tex]

b). [tex]$0.018 \sin 15=1 \times \lambda$[/tex]

[tex]$\lambda=4.66 \mathrm{~mm}$[/tex]

Frequency;

[tex]$\begin{aligned}& \mathrm{f}=\mathrm{c} / \mathrm{lambda}=\left(3^* 10^8\right) /\left(4.66^* 10^{-3}\right) \\& \mathrm{f}=6.44^* 10^{10} \mathrm{~Hz}\end{aligned}$[/tex]

To know more about Frequency visit:

https://brainly.com/question/254161

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The complete question is-

Raise your hand and hold it flat. Think of the space between your index finger and your middle finger as one slit, and think of the space between middle finger and ring finger as a second slit.

(a) Consider the interference resulting from sending coherent visible light perpendicularly through this pair of openings. Calculate the angle between adjacent zones of constructive interference, assuming the width of your middle finger to be 2.7 cm and the wavelength of the light to be 700 nm.

(b) To make the angles in the interference pattern easy to measure with a plastic protractor (e.g., for which the angle between the central maximum and the adjacent ones is 15), you should use an electromagnetic wave with what frequency?

Hz

How is this wave classified on the electromagnetic spectrum?

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