Find the best answers to your questions at Westonci.ca, where experts and enthusiasts provide accurate, reliable information. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.
Sagot :
If there is another element of the same set between any two members of a set, we can say that the set is dense.
We'll show that the first choice—3.14 and pi—is the right one.
To prove that the set of irrational numbers contains a lot of real numbers, we must first discover an irrational number that lies between two specified real numbers.
In order to extend this to the real set, which is the union of irrational numbers and rational numbers, we should be able to find an irrational number between a rational number and an irrational number (or between an irrational number and a rational number). This is because we know that irrational numbers are dense (between two irrational numbers we can find another irrational number).
The first option, which has one of each, will then be the right choice.
Pi is irrational, while 3.14 is rational.
Finding an irrational number between these two indicates that the real set contains many irrational numbers.
(Note that the third option likewise has an irrational and a rational number, but the first one, [tex]e^{2}[/tex], is larger than the second one[tex]\sqrt{54}[/tex], thus it is written wrongly; for this reason, we did not choose it.)
To know more about Irrational and rational numbers
https://brainly.com/question/17450097
#SPJ4
We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.
