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Sagot :
The concentration of potassium permanganate solution is 0.015 mM.
Use the equation given below to calculate the molarity of solution,
Mili molarity of the solution = [Mili moles of solute × 1000]/[Volume of solution in mL]
Given,
Moles of the solute = 4.6 × 10⁻³ mmol
Volume of the solution = 300 mL
Substituting the values we get,
Mili molarity of the solution = [Mili moles of solute × 1000]/[Volume of solution in mL]
Mili molarity of the solution = [4.6 × 10⁻³ × 1000]/300 = 0.015 mM
Hence the mili molarity of the solution of potassium permanganate is 0.015 mM.
Learn more about mili molarity of the solution from the link given below.
https://brainly.com/question/13265677
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