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Write an equation in slope-intercept form of the line that passes through the points (2, 15) and (5, 21).

Sagot :

The equation of the line that passes through the points (2, 15) and (5, 21) is y = 2x + 11

The coordinates of the first point = (2, 15)

The coordinates of the second point = (5, 21)

The slope of the line = [tex]\frac{y_2-y_1}{x_2-x_1}[/tex]

Substitute the values in the equation

The slope of the line = (21-15) / (5-2)

= 6 / 3

= 2

The slope intercept form is

y = mx + b

Substitute the values

15 = 2(2) + b

15 = 4 + b

b = 15 - 4

b = 11

Substitute the values in the equation

y = 2x + 11

Therefore, the equation of the line in slope intercept form is y = 2x + 11

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