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Sagot :
The balance the equation below in acidic medium are :
6Fe²⁺ + 2Cr₂O₇²⁻ + 14H⁺ ----> 6Fe³⁺ + 2Cr³⁺ + 7H₂O
1) The equation is given as :
Fe²⁺ + Cr₂O₇²⁻ -----> Fe³⁺ + Cr³⁺
oxidation half : Fe²⁺ ---> Fe³⁺
reduction half : Cr₂O₇²⁻ ---> Cr³⁺
2) first balance the oxidation half :
Fe²⁺ ---> Fe³⁺ + e⁻
this equation is balanced.
3) balanced reduction half :
Cr₂O₇²⁻ ---> 2Cr³⁺
add seven H₂O molecule on the right side to balance the O atoms.
Cr₂O₇²⁻ ---> 2Cr³⁺ + 7 H₂O
to balance 14 H atom add 14 H⁺ on the left side :
Cr₂O₇²⁻ + 14H⁺ ---> 2Cr³⁺ + 7 H₂O
now, balance the charge :
Cr₂O₇²⁻ + 14H⁺ + 6e⁻ ---> 2Cr³⁺ + 7 H₂O
6 electrons are gained by the reduction half , so multiply 6 in oxidation equation
6Fe²⁺ ---> 6Fe³⁺ + 6e⁻
add both the equation we get :
6Fe²⁺ + 2Cr₂O₇²⁻ + 14H⁺ 6e⁻ ----> 6Fe³⁺ + 2Cr³⁺ + 7H₂O + 6e⁻
The final balanced equation is given as :
6Fe²⁺ + 2Cr₂O₇²⁻ + 14H⁺ ----> 6Fe³⁺ + 2Cr³⁺ + 7H₂O
To learn more about balanced equation here
https://brainly.com/question/10053651
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