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The tide, or depth of the ocean near the shore, changes throughout the day. The depth of the bay can be modeled by d = 35 - 28 cos (π/6. 2 t)



where d is the depth in feet and t is the time in hours. Consider a day in which t = 0 represents 12:00 A. M. At what time is the water depth 14 feet.


(please include explanation)


Sagot :

The exists no solution for which the water depth 14 feet in the ocean near the shore.

Explain the term time period?

  • A time period (T) is the length of time it takes for one complete vibration cycle to pass over a certain location.
  • As the frequency of a wave rises, so does its period. The length of time is expressed in "seconds."

We determine the function's period since that is the number of it takes hours for the ocean to return to its original depth of a specific number of feet.

The function's duration is 2π/ (π/6.2) = 12.4 hours.

When t = 0, midnight, or 12:00AM, it is low tide.

As a result, the next low tide will occur at 12:24 PM, or t = 12.4, 12.4 hours from now.

A high tide will occur halfway between those two low tides, at t=6.2 hours after midnight, or at 6:12AM.

Another high tide will occur at t=18.6 hours after midnight, or at 6:36 PM, 12.4 hours later.

If t = 0 is used in the equation, the low tide occurs at that time;

d = 35 - 28cos(pi/6.2)t

d = 35-28cos(pi/6.2)0

d = 35-28cos(0)

d = 35-28(1)

d - 35-28

d = 7

Therefore, there will never be 4 feet there because the lowest depth that may exist is 7 feet.

Thus, the exists no solution for which the water depth 14 feet in the ocean near the shore.

To know more about the time period, here

https://brainly.com/question/9112078

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