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when the concentration of a and b were 0.023 m and 0.054 m, the reaction rate was 8.31x10-2 m/sec, calculate the value for k (with units).

Sagot :

The reaction takes place in third order. The rate constant of the reaction for the given rate and concentrations is 1.23 × 10³ mol⁻² L² /s.

What is reaction rate?

The rate of a reaction is the rate of increase in the concentration of products or rate of decrease in the concentration of the reactants.

For the given reaction, the rate law is written as:

rate = k[A][B]²

[A] = 0.023

[B] = 0.054

rate = 8.31 ×10⁻² M/s

Rate constant k = rate/[A] [B]²

K = 8.31 ×10⁻² M/s/(0.023 × 0.054²)

  = 1.23 × 10³ mol⁻² L² /s

Therefore, the rate constant for the reaction is 1.23 × 10³ mol⁻² L² /s.

To find more on rate law, refer here:

https://brainly.com/question/4222261

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Your question is incomplete. But your complete question probably was:

The rate of a reaction is, Rate = k[A][B]2.when the concentration of a and b were 0.023 m and 0.054 m, the reaction rate was 8.31x10-2 m/sec, calculate the value for k (with units).

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