Explore Westonci.ca, the top Q&A platform where your questions are answered by professionals and enthusiasts alike. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.
Sagot :
First take all percents and make them grams. Since you're not given a overall molar mass you can assume it is 100 and therefore the percents are their masses.
So you have 14.31g Carbon, 1.2g Hydrogen, and 84.49g of Chlorine. Next you divide each by their molar masses to get moles of each.
Carbon= 14.31g Hydrogen= 1.2g Chlorine= 85.49g
12.01g 1.01g 35.45g
= 1.19moles = 1.188moles = 2.411moles
Next you divide each of those numbers by the smallest, in this case, Hydrogen.
Thus,
Carbon= 1.19moles Hydrogen= 1.188moles Chlorine= 2.411moles
1.188moles 1.188moles 1.188moles
=1.002 =1 =2.02
These are all close enough to round, so your final empirical formula is: CHCl2
Hope that helps!!
So you have 14.31g Carbon, 1.2g Hydrogen, and 84.49g of Chlorine. Next you divide each by their molar masses to get moles of each.
Carbon= 14.31g Hydrogen= 1.2g Chlorine= 85.49g
12.01g 1.01g 35.45g
= 1.19moles = 1.188moles = 2.411moles
Next you divide each of those numbers by the smallest, in this case, Hydrogen.
Thus,
Carbon= 1.19moles Hydrogen= 1.188moles Chlorine= 2.411moles
1.188moles 1.188moles 1.188moles
=1.002 =1 =2.02
These are all close enough to round, so your final empirical formula is: CHCl2
Hope that helps!!
Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.
