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Conservation of Momentum - A 5 kg mass has a speed of 3 m/s to the right when it hits and sticks to a 4 kg mass. If the final combined speed is 2 m/s to the right, what was the initial velocity of the second object. Pick the closest answer. A) 1.2 to the right B) 1.2 to the left C) 0.75 to the right D) 0.75 to the left

Sagot :

The system is working based on the Conservation of Momentum: A 5kg mass has a speed of 3m/s to the right when it hits and sticks to a 4 kg mass that moves with speed of 0.75m/s to the right (C). Both mass then move together with 2m/s to the right.

Conservation of momentum states that the total momentum of a system remains constant.

P = P'

Momentum is the product of a particle's mass and velocity. Momentum could be formulized as:

P = m.v

From the case, we know that:

m1 = 5kg

m2 = 4kg

v1 = 3m/s to the right

v1' = v2' = v' = 2m/s to the right

v2 = ?

Based on the conservation of momentum concept, we know that:

P = P'

where:

P = m.v

Hence:

P = P'

m1.v1 + m2.v2 = (m1 + m2)v'

5 (3) + 4 (v2) = (5+4) 2

15 + 4v2 = 18

4v2 = 3

v2 = 0.75 m/s --> because v2 positive, hence m2 is moving to the right

Learn more about Conservation of Momentum here: https://brainy.com/question/24989124

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