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If 75. 0 ml of a 0. 20 m solution of sodium nitrate is mixed with 25. 0 ml of a 0. 10 m solution of barium nitrate, what is the molar concentration of nitrate ions in the resulting solution?.

Sagot :

The molar concentration of nitrate ions in the resulting solution is 0.20M.

What is molar concentration?

Molar concentration, also known as molarity, quantity concentration, or substance concentration, is a unit used to describe the amount of a substance in a solution expressed as a percentage of its volume. The number of moles per liter, denoted by the unit symbol mol/L or mol/dm3 in SI units, is the most often used unit denoting molarity in chemistry. One mol/L of a solution's concentration is referred to as one molar, or 1 M.

Now let us come to our problem statement;

Nitrate from NaNO₃:

75.0 mL × 0.20 M = 15 mmol NaNO₃ = 15 mmol NO₃⁻

Nitrate from Ba(NO₃)₂:

25.0 mL × 0.10 M = 2.5 mmol Ba(NO₃)₂

2.5 mmol Ba(NO₃)₂ × [tex]\frac{2mmol NO3}{1mmol Ba(NO3)2}[/tex]  = 5.0 mmol NO₃⁻

So the final number of NO₃⁻ moles is (15 + 5) 20 mmol.

The final volume is (75 + 25) 100 mL.

So the molar concentration is:

20 mmol / 100 mL = 0.20 M

The molar concentration of nitrate ions in the resulting solution is 0.20M.

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