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consider a reaction where the kc is 12.6 and the rate constant for the reverse reaction is 5.1 x 10^-2 sec. what is the rate constant

Sagot :

Using the equilibrium constant mean formula, the rate constant of the reverse reaction is 64.26 × 10∧-2 sec.

What does the Equilibrium constant mean?

The value of a chemical reaction's reaction quotient at chemical equilibrium, a condition that a dynamic chemical system approaches when enough time has passed and at which its composition has no discernible tendency to change further, is the equilibrium constant for that reaction. The equilibrium constant is independent of the initial analytical concentrations of the reactant and product species in the mixture for a given set of reaction conditions. As a result, the composition of a system at equilibrium can be calculated from its initial composition using known equilibrium constant values. However, factors affecting the reaction such as temperature, solvent, and ionic strength may all affect the equilibrium constant's value.

Given;

Kc=12.6;

Rate of backward Reaction=Rb=5.1×10∧-2 sec;

Now,

Kc = [tex]\frac{Rf}{Rb}[/tex];

Rf = Kc × Rb;

⇒Rf = 12.6×5.1×10∧-2 = 64.26×10∧-2 sec.

⇒Rf = 64.26×10∧-2 sec.

Using the equilibrium constant mean formula, the rate constant of the reverse reaction is 64.26 × 10∧-2 sec.

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