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Sagot :
(a) The expected value is 48 and the standard deviation is 5.366 .
(b) The probability that this year's class will beat the record is 0.0250 .
In the question ,
it is given that ,
the number of students is (n) = 120
40% of graduates will go on to college , that means (p) = 0.4
Part(a)
the expected value is E(x) is
E(x) = n*p = 120*0.4 = 48 .
the standard deviation is √np(1-q) = √120*0.4*0.6 = √28.8 ≈ 5.366
Part(b)
Using normal distribution for approximation ,
μ = 48 , σ = √28.8 and z = (x - 48)/√28.8 .
P(class will beat the record) = P(x>58)
= P(x>58.5) continuity correlation
= P(Z > (58.5 - 48)/√28.8) = P(Z > 1.96) that is
= 0.0250 .
Therefore , (a) expected value = 48 , standard deviation = 5.366
(b) the required probability is 0.0250 .
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