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PLEASE SHOW STEPS WILL MARK BRAINLIEST

The following graph shows a top-opening parabola.

What is the vertex form of the equation that represents this parabola?
Responses

y=(x−9)2−1y is equal to open paren x minus 9 close paren squared minus 1
y=(x+1)2−9y is equal to open paren x plus 1 close paren squared minus 9

y=(x+9)2−1y is equal to open paren x plus 9 close paren squared minus 1
y=(x−1)2−9

PLEASE SHOW STEPS WILL MARK BRAINLIEST The Following Graph Shows A Topopening Parabola What Is The Vertex Form Of The Equation That Represents This Parabola Res class=

Sagot :

sqdancefan

Answer:

  (b)  y=(x+1)²−9

Step-by-step explanation:

You want the vertex form equation of the graphed parabola, which opens upward and has its vertex at (-1, -9).

Vertex form

The vertex form equation for a parabola with vertex (h, k) is ...

  y = (x -h)² +k

The vertex of the parabola shown is (h, k) = (-1, -9). Using these values in the equation gives ...

  y = (x +1)² -9

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Additional comment

The equation may include a scale factor that multiplies the square. Here, the curve rises 1 unit for 1 unit either side of the vertex, so the scale factor is 1. (The rise at ±1 from the vertex is the scale factor.)

Steps: (1) read the vertex coordinates from the graph; (2) put those coordinates in the vertex form equation; (3) check to see that the vertical scale factor is 1.

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