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Sagot :
The answer is 7200 milliliters, but since moles are a significant quantity, you'd need a very, very large volume of solution, making this impractical for the sake of many experiments. We will translate the molarity provided into normalcy. It is evident from the description above that 5 ml of 1M [H2S O 4] is needed to neutralize 10 ml of 1N NaOH.
For "NaOH, M=N," The formula is "N (1)V (1)=100 ml xx 1N=100" ml (N) N (2)V (2)=10mlxx10 N=100' ml (N) for "H (2)SO (4)" Thus, "N (1)V (1)=N (2)V (2)" is true. You may clear your doubts and achieve good exam results with the help of step-by-step solutions provided by specialists. NaOH has a 1M molecular weight. The amount of a substance in a specific volume of solution is known as its molarity (M). The number of moles of a solute per litre of a solution is known as molarity. The molar concentration of a solution is another name for molarity. We divide the number of moles of solute by the total volume of litres of solution to determine the molarity of a solution. The moles of solute per litre of solution is measured as molarity. For instance, when table salt is dissolved in water, water serves as both the solution and the solute. Sodium chloride weights 58.44 grams per mole. One molar solution, or 1M, is created by dissolving 58.44 grams of sodium chloride in one litre of water.
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