The angle for third order maximum is [tex]0.481^{\circ}[/tex] .
Given that, wavelength of yellow light is 605-nm. Distance between the slits on which the light is falling is 0.105 mm.
The angle for the the third order maximum can be calculated by the formula given below.
[tex]m \lambda=2 d \sin \theta[/tex]
where, λ is the wavelength of light, is the distance between the slits and is the order of diffraction.
For the third order,[tex]m=3[/tex].
Substituting the values in the above formula, we get the angle for the third order maximum.
[tex]\begin{aligned}& 3 \times 605 \times 10^{-9}=2 \times 0.105 \times 10^{-3} \times \sin \theta \\& \sin \theta=\frac{3 \times 605 \times 10^{-9}}{2 \times 0.105 \times 10^{-3}}\end{aligned}[/tex]
Simplifying the above equation as,
[tex]\begin{aligned}& \sin \theta=0.0084 \\& \theta=\sin ^{-1}(0.0084) \\& \theta=0.481^{\circ}\end{aligned}[/tex]
Hence, the angle for third order maximum is [tex]0.481^{\circ}[/tex].
What is the wavelength?
A quality of a wave that is the distance between similar points between two continually waves is called wavelength.
To know more about the wavelength, visit:-
https://brainly.com/question/22866521
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