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Sagot :
The equation of the line is y = 1/5(x + 37). The standard equation of a instantly line is y = mx + c, in which m is the gradient, and y = c is the cost in which the road cuts the y-axis.
This range c is known as the intercept at the y-axis. The equation of a instantly line with gradient m and intercept c at the y-axis is y = mx + c. The equation of a instantly line is y=mx+c y = m x + c m is the gradient and c is the peak at which the road crosses the y -axis, additionally referred to as the y -intercept.
Since equation have new line which is parallel y = 1/5(x + 4), and 1/5 is most the gradient for the line y = 1/5(x + 4), this is the new line is 1/5.
Using the equation we can form a line in slope-point form,
[tex]\frac{y-y_{1} }{x-x_{1} } = m[/tex]
where (x₁, y₁) = (3, 8) and m = 1/5
Substituting the values for all variables into the equation, we have
[tex]\frac{y-y_{1} }{x-x_{1} } = m\\\frac{y-8 }{x-3 } = m\\[/tex]
Cross-multiplying. we have
5(y - 8) = x - 3
Expanding the bracket, we have
5y - 40 = x - 3
5y = x - 3 + 40
5y = x + 37
y = 1/5(x + 37)
So, the equation of the line is y = 1/5(x + 37)
Learn more about equation of a line here:
brainly.com/question/15587122
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