Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
The velocity of the second ball after the collision is 2.8m/sec if both first and second ball collide head-on a table.
We are given that there is no role of friction and collision is perfectly elastic, it means momentum conservation is possible.
Since, all collision is happening along a single axis. So, we assume all collision is happening in x-axis.
Now, we need to conserve momentum along x-axis which states that initial momentum of the system is equal to final momentum of the system.
Now, we know that momentum is given by the product of mass and velocity.
So, initial momentum of the first ball is =0.50×12=6.00kg-m/sec
initial momentum of the second ball is=0.75×(-16.0)= -12.00kg-m/sec
Final momentum of first ball is =0.50 × (-21.6)m/sec = -10.8kg-m/sec
Final momentum of second ball =0.75×vkg-m/sec
Therefore, 6+(-12) = (-10.8) +(0.75v)
=> -6 =-10.8+0.75v
=>0.75v=10.8-6
=>0.75v=4.8
=>v=4.8/0.75
=>v=2.8m/sec
Hence, velocity of second ball is 2.8m/sec.
To know more about elastic collision, visit here:
https://brainly.com/question/2356330
#SPJ4
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.
