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Sagot :
The velocity of the second ball after the collision is 2.8m/sec if both first and second ball collide head-on a table.
We are given that there is no role of friction and collision is perfectly elastic, it means momentum conservation is possible.
Since, all collision is happening along a single axis. So, we assume all collision is happening in x-axis.
Now, we need to conserve momentum along x-axis which states that initial momentum of the system is equal to final momentum of the system.
Now, we know that momentum is given by the product of mass and velocity.
So, initial momentum of the first ball is =0.50×12=6.00kg-m/sec
initial momentum of the second ball is=0.75×(-16.0)= -12.00kg-m/sec
Final momentum of first ball is =0.50 × (-21.6)m/sec = -10.8kg-m/sec
Final momentum of second ball =0.75×vkg-m/sec
Therefore, 6+(-12) = (-10.8) +(0.75v)
=> -6 =-10.8+0.75v
=>0.75v=10.8-6
=>0.75v=4.8
=>v=4.8/0.75
=>v=2.8m/sec
Hence, velocity of second ball is 2.8m/sec.
To know more about elastic collision, visit here:
https://brainly.com/question/2356330
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