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determine the ph change when 0.085 mol hi is added to 1.00 l of a buffer solution that is 0.392 m in hclo and 0.356 m in clo-.

Sagot :

The pH change for the given acidic buffer solution is 0.22.

HClO and ClO- is an acidic buffer, and with addition of HI, the concentration of acid increases while the concentration of salt decreases.

pH=pKa +log (salt/acid)

=7.54+log (0.326/0.369)

=7.54-0.05

=7.49

On adding Hydrogen iodide,

pH=pKa+ log((0.326-0.085)/(0.369+0.085))

=7.54+log (0.241/0.454)

=7.54-0.27

=7.27

Thus, the value of pH change cab be calculated as follows:

=7.27-7.49

=0.22

To learn more about pH check the link below:

https://brainly.com/question/172153

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