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a runner moving at a speed of 7.20 m/s rounds a bend with a radius of 36m. what is the centripetal acceleration of the runner?

Sagot :

The centripetal acceleration of the runner is 1.44m/sec²  if he is moving at a speed of 7.20m/sec while bending a radius of 36m.

Centripetal acceleration increase is characterized as the property of the movement of an item, crossing a roundabout way. Any item that is moving all around and has a speed increase vector pointed towards the focal point of that circle is known as Centripetal speed increase.

You probably seen different instances of centripetal speed increase in your regular daily existence. In the event that you drive a vehicle around a circle, your vehicle is going through centripetal speed increase and a satellite circling the earth likewise follows a centripetal speed increase. Centripetal means towards the middle.

Centripetal acceleration increase can be estimated in meters each second as it is the quantity of meters each second by which your speed changes consistently. At the point when an item is moving in a round movement, it very well may be estimated by utilizing the accompanying condition

[tex]a_c[/tex]=(v²)/r

Where,

[tex]a_c[/tex]   is the centripetal acceleration increase in m/sec²

v is the speed in m/sec

r is the sweep in m.

So, we have v=7.20m/sec, r=36m.

So,[tex]a_c[/tex]=(7.20)²/36

=>[tex]a_c[/tex]=(51.84)/36

=>[tex]a_c[/tex]=1.44m/sec²

Hence, centripetal acceleration is 1.44m/sec².

To know more about centripetal acceleration, visit here:

https://brainly.com/question/14465119

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