Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
At the significance level, 0.01
p-Value=0.973 > 0.01 which implies fail to reject null hypothesis and no evidence to support the claim.
So, there is no reason to believe that this increase in substrate concentration causes an increase in the mean velocity of the reaction of more than 0.5 micromole per 30 minutes.
We have given that,
A study conducted to see if increasing the substrate concentration has an appreciable effect on the velocity of a chemical reaction.
x₁-bar = 8.8 micromoles
Standaard deviations, s₁= 1.2
x₂-bar = 7.5 ; s₂ = 1.5
n₁ = 12 ; n₂ = 15
significance level = 0.01
Consider the Null hypothesis and alternative hypothesis othesis
H₀ : μ = 0.5
Hₐ : μ > 0.5
Consider,
Pooled Standard Deviation = √(((n₁ - 1)s₁² + (n₂- 1)s₂²)/(n₁ + n₂-2))
plugging all known values
= sqrt(((12-1)(1.2²) + (15 -1)(1.5²))/(12+15-2))
Sp = 1.3761
Now , test statistic :
t =((x₁-bar - x₂-bar) - 0.5) / (Sp×√(1/n₁+ 1/n₂))
substitute all known values we get,
= ((8.8 - 7.5) - 0.5) / (1.3761× sqrt(1/12 + 1/15))
=> t = 1.5
Degree of freedom = n₁+ n₂ - 2
= 12 + 15 - 2
= 25
Now the p-value corresponding to t = 1.5 & df = 25 is 0.073
Here p-value > 0.01 (significance level) thus, we fail to reject null hypothesis.
So there is no enough evidence to support the claim.
To learn more about Hypothesis testing, refer:
https://brainly.com/question/4232174
#SPJ4
We appreciate your time. Please come back anytime for the latest information and answers to your questions. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.