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Consider the data set. 2, 3, 5, 6, 7. use the defining formula to compute the sample standard deviation s. (round your answer to two decimal places.)

Sagot :

The sample standard deviations of the data set 2, 3, 5, 6, 7 rounded up to 2 decimal spaces is 2.07.

The term "standard deviation"  refers to a measurement of the data's dispersion from the mean. A low standard deviation implies that the data are grouped around the mean, whereas a large standard deviation shows that the data are more dispersed. Think about the following data: 2, 1, 3, 2, 4.

The average and the total square of the observations' departures from the mean will be 2.4 and 5.2, respectively. This means that (5.2/5) = 1.01 will be the standard deviation. The standard deviation reveals the degree of data skewedness. It gauges how far away from the mean each observed value is. Approximately 95% of values in any distribution will be within two standard deviations of the mean.

Number of data points (n)=5

Mean (x)= (2+3+5+6+7)/5= 4.6

Here x = 2, 3, 5, 6, 7

(x-x)  = -2.6, -1.6, 0.4, 1.4, 2.4

[tex](x-X)^{2}[/tex] = 6.76, 2.56, 0.16, 1.96, 5.76

∑[tex](x-X)^{2}[/tex] = 17.2

Sample standard deviation :

[tex]\sqrt{\frac{(x-X)^{2}}{n-1} } \\\\\sqrt{\frac{17.2}{4} } \\\\[/tex]

= 2.07

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