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for the following assembly program, if the content of d[9] is 3. what is the value in r5 and r6 after the program completes?

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For the following assembly program, assuming that the content of D[9] is 2, the value in R5 and R6 after the program completes will be 3 and 2 respectively.

What is the explanation for the above?

The program starts by moving the value 1 into R6 and moving the value 9 into R5. Then it jumps to the label label1 if R5 is equal to 0. Since R5 is not equal to 0, it does not jump to the label and instead adds the values in R5 and R6, which are 9 and 1 respectively, to produce the value 10 in R5.

Next, the program adds the values in R5 and R6 again, producing the value 11 in R5. Finally, it subtracts the value in R6 from the value in R5, which is 11 and 1 respectively, to produce the value 10 in R6. Therefore, at the end of the program, R5 has a value of 3 and R6 has a value of 2.

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Full Question:

For the following assembly program, assuming that the content of D[9] i s 2. What is the value in R5 and R6 after the program completes? MOV R6, #1 MOV R5, 9 JMPZ R5, label1 ADD R5, R5, R6 label1: ADD R5, R5, R6 SUB R6, R5, R6

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