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Figure shows (Figure 1) a low-pass filter; the output voltage is taken across the capacitor in an L-R-C series circuit Part A Derive an expression for Vout/Vs, the ratio of the output and source voltage amplitudes, as a function of the angular frequency w of the source OV = wc R+W L- e a dew.L everyone 0 o Vot wc/r-wc-a wC /Re-(w 'wc/r+(w It is 1 Vout = Submit Request Answer Figure < 1 of 1 Part B Find an expression for Vout/V, when w is large. 0 1 0 ) (LC HE V O (LC) 0000 O (LC) w2

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The output voltage is measured across the capacitor in an L-R-C series circuit, and the expression for Vout/vs for a low-pass filter is 1/(1-w^2lc + (wcR)^2. depending on the angular frequency.

A linear shunt regulator's output voltage (LSR) is defined as the difference between the input voltage and the sum of the current flowing through the shunt resistance, and it is denoted by Vo = Vi- (io+Ish)*Rsh or output voltage = input voltage- (output current + shunt field current)*shunt field resistance. The angular frequency, also known as the angular frequency vector, is the size of the vector quantity called angular velocity. The rotational speed of an object is measured by its angular frequency. It is helpful in many scientific and mathematical fields since it makes it possible to comprehend a wide range of physical world objects' qualities.

Vout = Vs/(R+jwl+1/jwc)

Vout/vs = 1/(1-w^2lc + (wcR)^2

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