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The terms is given by the formula b=a+(n-1)d solve for n in terms of a,b, and d

Sagot :

thisisbenmanley
[tex]b=a+(n-1)d\\b-a=(n-1)d\\\frac{b-a}{d}=n-1\\\frac{b-a}{d}+1=n[/tex]
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