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Sagot :
The total displacement of the airplane is found to be 400 km West
First of all the airplane Travels 1000 km in the direction of west and then the airplane Travels 600 km in the direction of East.
Now if we assume the is direction to be the x-axis and the west direction to be the negative access because they both are completely opposite of each other, then we can define the total displacement has the difference between the initial position U and the final position V of the airplane which will be given by,
D = (V-U)
Now, putting all the values,
D = -1000-(-600)
D = -400km.
So we can say that the total displacement of the airplane is -400 km in the direction of West.
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