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find the flux through the boundary of the rectangle for fluid flowing along the vector field .

Sagot :

For fluid moving in a vector field, the flux through the rectangle's perimeter is 750.52.

Flux = ∫ F. X ds

Flux = ∫∫ delta. F da (by divergence theorem)

delta. F = d/dx(x³+4) + d/dy(ycos(3x))

            = 3x² + cos(3x)

So flux = ∫∫ 3x² + cos(3x) dy dx

            = ∫ (3x² + cos(3x)) (y)⁶₀ dx

            = 6 ∫ 3x² + cos(3x) dx

After evaluating,

             = 6(125 + sin(15)/3)

             = 750.52

Therefore, the flux through the boundary of the rectangle for fluid flowing along the vector field is 750.52

To learn more about flux click here:

brainly.com/question/14527109

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