Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

A 8.00 L tank at 22.8 °C is filled with 6.88 g of sulfur hexafluoride gas and 2.33 g of dinitrogen monoxide gas. You can assume both gases behave as ideal gases under these conditions. Calculate the mole fraction and partial pressure of each gas, and the total pressure in the tank.

Sagot :

Mole fraction of SF6 is  0.081 and N₂O is  1.107 . Partial pressure of  SF6 is 0.126 atm and N₂O is  0.273 atm .

In chemistry, what does a mole fraction mean?

the proportion of the moles with one component to the total moles of all the components in a solutions or other mixture.

Briefing:

Mole fraction of each gas,

Sulfur hexafluoride molar mass = 146.1 g / mol) = SF6

moles  SF6 = 6.88 g x 1 / 146.1 = 0.047 moles

dinitrogen monoxide =  N₂O = 44.013 g/mol

moles  N₂O = 2.33 g  x 1 /44.013 = 0.53 moles

Total moles =  0.047 moles +  0.53 moles = 0.577 moles

Mole fraction  SF6 =  0.047  /  0.577 = 0.081

Mole fraction N₂O =  0.53 / 0.577 = 1.107

by using formula, we can determine the partial pressure for each gas

PV = nRT

P = pressure = ?

V = volume = 8.00 L

n = moles = 0.577 moles

R = gas constant = 0.0821 Latm/Kmol

T = temperature in K = 22.8 °C + 273.15 = 295.95 K

P = nRT/V = (0.577)(0.0821)(295.95) / 8.00

P = 1.75 atm = Total pressure

Partial pressure SF6 = 1.75 atm x 0.081 = 0.126 atm

Partial pressure N₂O = 1.75 atm x 1.107 = 0.273 atm

To know more about mole fraction visit:

https://brainly.com/question/12127540

#SPJ4