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Sagot :
Mean = 54.52
V(X) = 3.2712
S.D = 1.8086
To calculate the mean (expected value) of a binomial distribution B(n, p) you need to multiply the number of trials n by the probability of successes p , that is: mean = n × p
Where, n= 58
p = 0.94
Therefore, mean = 54.52
To find the Variance of the given binomial distribution
Variance = np(1-p)
=58 X 0.94 ( 1- 0.94)
= 54.52 X 0.06
V(X) = 3.2712, when we know the variance and the mean then we can calculate the standard deviation easily
To find the standard deviation of the given binomial experiment = [tex]\sqrt{np(1-p)}[/tex]
= [tex]\sqrt{3.2712}[/tex]
S.D = 1.8086
To know more about binomial distribution
https://brainly.com/question/29732172
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