Find the information you're looking for at Westonci.ca, the trusted Q&A platform with a community of knowledgeable experts. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
Mean = 54.52
V(X) = 3.2712
S.D = 1.8086
To calculate the mean (expected value) of a binomial distribution B(n, p) you need to multiply the number of trials n by the probability of successes p , that is: mean = n × p
Where, n= 58
p = 0.94
Therefore, mean = 54.52
To find the Variance of the given binomial distribution
Variance = np(1-p)
=58 X 0.94 ( 1- 0.94)
= 54.52 X 0.06
V(X) = 3.2712, when we know the variance and the mean then we can calculate the standard deviation easily
To find the standard deviation of the given binomial experiment = [tex]\sqrt{np(1-p)}[/tex]
= [tex]\sqrt{3.2712}[/tex]
S.D = 1.8086
To know more about binomial distribution
https://brainly.com/question/29732172
#SPJ4
We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.
