Answered

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the probability that a restaurant passes its health department inspection is 0.94. the owners of 58 restaurants are surveyed to see if their restaurants passed inspection. For each binomial experiment described, find the mean, the variance and the standard deviation!

Sagot :

Mean = 54.52

V(X) = 3.2712

S.D = 1.8086

To calculate the mean (expected value) of a binomial distribution B(n, p) you need to multiply the number of trials n by the probability of successes p , that is: mean = n × p

Where, n= 58

p = 0.94

Therefore, mean = 54.52

To find the Variance of the given binomial distribution

Variance = np(1-p)

=58 X 0.94 ( 1- 0.94)

= 54.52 X 0.06

V(X) = 3.2712, when we know the variance and the mean then we can calculate the standard deviation easily

To find the standard deviation of the given binomial experiment = [tex]\sqrt{np(1-p)}[/tex]

= [tex]\sqrt{3.2712}[/tex]

S.D = 1.8086

To know more about binomial distribution

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