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taking logarithms and antilogarithms is necessary to solve many chemistry problems. for practice, complete the following table, where is a number.

Sagot :

N = 7.35 ln in row 1; N Equals ln(7.35) = 1.995 logarithmic N = log(7.35) (7.35) To solve many chemical problems, logarithms and antilogarithms must be used.

Antilogarithms: How are they solved?

The bases of logarithm and antilog are both 2.7183. Logarithms and antilogarithms with bases of 10 need be multiplied by 2.303 to create natural logarithms and antilogarithms.

How are the antilogarithm and log calculated?

For both numbers, the base must be the same. Log b x y = p - q (= log b x - log b y is the outcome of taking logs on both sides. The inverse function of the difference in the two numbers' logarithms is what is used to divide them.

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