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suppose life expectancy for freezers has an unknown distribution with mean 16 years and standard deviation 2 years. a sample of size n

Sagot :

Standard error of the  of the standard deviation of 2 years with the mean  and the sample size of n will be 3

The parameter list is abbreviated (lower value, upper value, μ,

, α / √n

normal cdf: (85,92,90, 15 / √25

= 0.6997

To find the value that is two standard deviations above the expected value 90, use the formula:

value = ux + ( # of STDEVs ( αx / √n )

value = 90 + 2 (15 / √25 )= 96

The value that is two standard deviations above the expected value is 96. The standard error of the mean is

σ / √n = 15√25

= 3.

standard error of the mean is a description of how far that the sample mean will be from the population mean in repeated simple random samples of size n.

To learn more about the standard deviation

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