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14. In the figure (not drawn to scale), MO bisects ZLMN, m 2NMO = (6x +19)°, and m2LMO = (9x -
14). Solve for x and find ZLMN.
A. x= 11, m B. x= 11, m LMN = 170°
C. x=8, m ZLMN = 25°
D. x=8, m ZLMN = 54°

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